🇺🇸 CCSS Math · Grade 8

8.G.B.8: Distance between points on a grid

8.G.B.8 explained: using the Pythagorean Theorem to find the distance between two coordinate points, including negative coordinates. Free practice.

Common Core standard CCSS.Math.Content.8.G.B.8

Apply the Pythagorean Theorem to find the distance between two points in a coordinate system.

Grade
Grade 8
Domain
Geometry (G)
Cluster
Understand and apply the Pythagorean Theorem

Official wording from the Common Core State Standards for Mathematics (© 2010 National Governors Association Center for Best Practices and Council of Chief State School Officers). View on thecorestandards.org

What 8.G.B.8 means

Two points on a coordinate grid that do not line up horizontally or vertically are joined by a slanted segment, and a ruler is not much help. The trick is to see that segment as the hypotenuse of a right triangle whose legs run along the grid lines. For the points (1, 2) and (7, 10), the horizontal leg is 7 - 1 = 6 units and the vertical leg is 10 - 2 = 8 units, so the distance is √(6² + 8²) = √100 = 10 units.

Grade 8 students find these legs by counting or subtracting coordinates, taking care when points sit in different quadrants: from x = -3 to x = 5 is 8 units, not 2. Because the legs are squared, the order of subtraction does not matter, and a negative difference gives the same result. This standard prepares the ground for the distance formula in high school, but at this level the emphasis is on drawing the right triangle and understanding why the method works, which also helps with tasks like finding the perimeter of a shape plotted on a grid.

Students should be able to

  • Draw the right triangle formed by two points and the grid lines between them.
  • Find the horizontal and vertical leg lengths by subtracting coordinates.
  • Calculate the distance between two points using the Pythagorean Theorem.
  • Handle points in different quadrants and with negative coordinates.
  • Find the perimeter of a polygon on the coordinate plane using distances.

Common misconceptions

Subtracting across zero incorrectly

From -3 to 5 students often say 2 units. Counting on the grid, or computing 5 - (-3), gives 8.

Adding the legs instead of using the theorem

The distance from (0, 0) to (3, 4) is not 3 + 4 = 7. That is the route along the grid, not the straight-line distance, which is 5.

Mixing up x and y differences

Students subtract an x-coordinate from a y-coordinate. Keep the horizontal change (x values) and vertical change (y values) separate.

Forgetting the final square root

Reporting 100 instead of 10 is common. The sum of squares is the square of the distance, so take its root.

Worked example: points in different quadrants

Find the distance between A(-3, 1) and B(5, 7).

  1. Horizontal leg: 5 - (-3) = 8 units.
  2. Vertical leg: 7 - 1 = 6 units.
  3. Use the Pythagorean Theorem: d² = 8² + 6² = 64 + 36 = 100.
  4. Take the square root: d = 10 units.

Answer: The distance from A to B is 10 units.

Teaching 8.G.B.8

Have students plot the two points, draw the slope triangle with a colored pencil, and write the leg lengths on it before any calculation. A map task, such as distances between landmarks on a town grid, makes the method purposeful and shows the difference between a walking route along streets and a straight-line distance.

Assessment items usually show points on a grid or give coordinates and ask for the distance, sometimes to the nearest tenth. Encourage drawing even when coordinates are given, because the picture prevents sign errors.

5 practice questions

Original questions written for this standard. Choose an option or type your answer, then press Check. Every question has a worked explanation.

Score: 0 / 5(0 of 5 checked)
  1. 1.

    What is the distance between (0, 0) and (5, 12)?

    Answer and explanation

    Answer: 13

    The legs are 5 and 12. √(25 + 144) = √169 = 13.

  2. 2.

    What is the distance between (2, 3) and (5, 7)?

    Answer and explanation

    Answer: 5

    Horizontal leg 3, vertical leg 4. √(9 + 16) = 5.

  3. 3.

    What is the horizontal leg length between (-4, 2) and (6, 9)?

    Question 3 options
    Answer and explanation

    Answer: D) 10

    6 - (-4) = 10. Lengths are always positive.

  4. 4.

    To the nearest tenth, what is the distance between (1, 1) and (4, 3)?

    Answer and explanation

    Answer: 3.6

    Legs 3 and 2: √(9 + 4) = √13 ≈ 3.6.

  5. 5.

    Why does it not matter which point you subtract from which?

    Question 5 options
    Answer and explanation

    Answer: B) Because the differences are squared, so a negative result becomes positive

    Squaring a negative difference gives the same value as squaring the positive one, so the distance is unchanged.

Builds on

Leads to

  • HSG-GPE.B.7

    Use coordinates to compute perimeters of polygons and areas of triangles and rectangles, e.g., using the distance formula.^*

Teach 8.G.B.8

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FAQ

Is 8.G.B.8 the distance formula?

It covers the same idea, but grade 8 students are expected to use the Pythagorean Theorem with a drawn triangle. The general distance formula is formalized in high school.

Can 8.G.B.8 problems involve negative coordinates?

Yes. Points can be in any quadrant, so students need to find differences across zero carefully.

More grade 8 Geometry standards

8.G.A.1: Properties of rigid transformations8.G.A.2: Congruence through rigid motions8.G.A.3: Transformations on the coordinate plane8.G.A.4: Similarity through transformations8.G.A.5: Angles in triangles and parallel lines8.G.B.6: Proving the Pythagorean Theorem and its converse8.G.B.7: Applying the Pythagorean Theorem8.G.C.9: Volume of cylinders, cones and spheres
More practice on this topic →All Grade 8 math standards →Standards home →