🇺🇸 CCSS Math · Grade 7

7.EE.A.1: Equivalent linear expressions

7.EE.A.1 explained: expanding, factoring and simplifying linear expressions with rational coefficients, with misconceptions and free practice.

Common Core standard CCSS.Math.Content.7.EE.A.1

Apply properties of operations as strategies to add, subtract, factor, and expand linear expressions with rational coefficients.

Grade
Grade 7
Domain
Expressions & Equations (EE)
Cluster
Use properties of operations to generate equivalent expressions

Official wording from the Common Core State Standards for Mathematics (© 2010 National Governors Association Center for Best Practices and Council of Chief State School Officers). View on thecorestandards.org

What 7.EE.A.1 means

Expressions such as 3(2x - 5) - (x - 4) and 5x - 11 look nothing alike, yet they give the same value for every x. They are equivalent, and seventh graders learn to move from one to the other using the properties of operations: the distributive property to expand or factor, the commutative and associative properties to reorder and regroup, and combining like terms to tidy the result.

The expressions here are linear, meaning the variable is never squared or multiplied by itself, and the coefficients can be any rational number: -2, 0.5, 3/4. Students expand -2(3a - 4) into -6a + 8, factor 6x + 15 as 3(2x + 5) by pulling out the greatest common factor, and subtract a whole expression by distributing the negative sign across every term. A powerful habit is checking equivalence by substituting a number: if two expressions give different values for x = 2, they cannot be equivalent.

Students should be able to

  • Expand expressions like -2(3a - 4) using the distributive property, including negative and fractional coefficients.
  • Factor a linear expression by its greatest common factor, such as 6x + 15 = 3(2x + 5).
  • Combine like terms with rational coefficients, such as 0.5x + 1.25x = 1.75x.
  • Subtract an expression in parentheses by distributing the negative sign to every term.
  • Test whether two expressions are equivalent by substituting values for the variable.

Common misconceptions

Distributing to the first term only

Writing 4(x + 3) as 4x + 3 is very common. Drawing arrows from the 4 to every term inside the parentheses, or using an area model, makes the missing product visible.

Losing the negative when subtracting a group

In 7y - (2y - 3), the subtraction applies to both terms, giving 7y - 2y + 3. Students who write - 3 have only negated the first term.

Combining unlike terms

Students sometimes simplify 2x + 7 to 9x. A quick check with x = 1 (2 + 7 = 9, but 9x = 9) can hide the error, so test a second value such as x = 2.

Factoring out a number that is not common

Writing 6x + 15 = 6(x + 15) undoes incorrectly. Expanding the factored form straight away shows whether it returns the original expression.

Worked example: expand, simplify and check

Simplify 3(2x - 5) - (x - 4). Then check your answer by substituting x = 2.

  1. Distribute the 3: 3(2x - 5) = 6x - 15.
  2. Distribute the negative sign: -(x - 4) = -x + 4.
  3. Combine like terms: 6x - x = 5x and -15 + 4 = -11, so the expression is 5x - 11.
  4. Check with x = 2: the original gives 3(4 - 5) - (2 - 4) = -3 + 2 = -1, and 5(2) - 11 = -1. They match.

Answer: 3(2x - 5) - (x - 4) = 5x - 11.

Teaching 7.EE.A.1

Algebra tiles and area models are worth the time: a rectangle 3 wide and (2x - 5) long shows exactly why every term gets multiplied. When students factor, the same model runs backward, asking what common width fits both parts.

Test items often present four expressions and ask which are equivalent to a given one, sometimes selecting more than one. Teach students to simplify each option fully or to substitute two different values before deciding.

6 practice questions

Original questions written for this standard. Choose an option or type your answer, then press Check. Every question has a worked explanation.

Score: 0 / 6(0 of 6 checked)
  1. 1.

    Simplify 4(x + 3) - 2x.

    Question 1 options
    Answer and explanation

    Answer: B) 2x + 12

    Expand: 4x + 12 - 2x. Combine the x terms: 4x - 2x = 2x. The result is 2x + 12.

  2. 2.

    Factor 6x + 15 using the greatest common factor.

    Answer and explanation

    Answer: 3(2x + 5) (also accepted: 3(2x+5), 3(5 + 2x))

    The greatest common factor of 6 and 15 is 3. 6x = 3 × 2x and 15 = 3 × 5, so 6x + 15 = 3(2x + 5).

  3. 3.

    Expand -2(3a - 4).

    Question 3 options
    Answer and explanation

    Answer: D) -6a + 8

    Multiply each term by -2: -2 × 3a = -6a and -2 × -4 = +8. The result is -6a + 8.

  4. 4.

    Simplify 0.5x + 1.25x.

    Answer and explanation

    Answer: 1.75x

    Both are x terms, so add the coefficients: 0.5 + 1.25 = 1.75. The result is 1.75x.

  5. 5.

    Which pair of expressions is equivalent?

    Question 5 options
    Answer and explanation

    Answer: B) 5(x - 2) and 5x - 10

    Distributing gives 5 × x - 5 × 2 = 5x - 10. The other expressions forget to multiply a term or change a sign.

  6. 6.

    Simplify 7y - (2y - 3).

    Answer and explanation

    Answer: 5y + 3 (also accepted: 5y+3, 3 + 5y)

    Distribute the negative sign: 7y - 2y + 3. Combine like terms: 5y + 3.

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FAQ

What are rational coefficients?

They are the numbers multiplying the variable when those numbers are fractions, decimals or negatives, such as -3/4 in -3/4 x or 0.6 in 0.6n.

How can students check that two expressions are equivalent?

Simplify both into the same form, or substitute at least two different values for the variable. Equivalent expressions always give equal results.

More grade 7 Expressions & Equations standards

7.EE.A.2: Rewriting expressions to understand a problem7.EE.B.3: Multistep problems with numbers in any form7.EE.B.4: Two-step equations and inequalities
All Grade 7 math standards →Standards home →