🇺🇸 CCSS Math · Grade 6

6.G.A.1: Area of triangles and polygons

6.G.A.1 explained: finding areas of triangles, parallelograms, trapezoids and polygons by composing and decomposing shapes, with an example and practice.

Common Core standard CCSS.Math.Content.6.G.A.1

Find the area of right triangles, other triangles, special quadrilaterals, and polygons by composing into rectangles or decomposing into triangles and other shapes; apply these techniques in the context of solving real-world and mathematical problems.

Grade
Grade 6
Domain
Geometry (G)
Cluster
Solve real-world and mathematical problems involving area, surface area, and volume

Official wording from the Common Core State Standards for Mathematics (© 2010 National Governors Association Center for Best Practices and Council of Chief State School Officers). View on thecorestandards.org

What 6.G.A.1 means

Rectangles are easy: length times width. Sixth grade asks students to find the area of everything else in the polygon family, and the method is to rearrange or split shapes into ones whose areas are already known. A right triangle is half of a rectangle, which is why its area is half of base times height. Any triangle can be boxed inside a rectangle or split into two right triangles, so the same formula, A = 1/2 bh, works for all of them.

Parallelograms work by cutting a triangle off one end and sliding it to the other, which makes a rectangle with the same base and height. Trapezoids can be split into a rectangle and triangles, or doubled into a parallelogram. Irregular polygons, like the floor plan of an L-shaped room, are decomposed into rectangles and triangles whose areas are added, or composed into a larger rectangle with pieces subtracted. Students apply these methods to real problems, so knowing which length is the height (always perpendicular to the base) matters more than memorizing formulas.

Students should be able to

  • Find the area of a right triangle as half of a rectangle.
  • Find the area of any triangle using A = 1/2 bh and explain where the formula comes from.
  • Find areas of parallelograms and trapezoids by rearranging or decomposing them.
  • Find the area of a composite polygon by splitting it into rectangles and triangles.
  • Identify the height of a shape as the perpendicular distance to the base.

Common misconceptions

Using the slanted side as the height

For a parallelogram with base 8 and slanted side 5, students compute 8 × 5. The height is the perpendicular distance between the bases, which is shorter than the slanted side.

Forgetting the 1/2 for triangles

Students who multiply base by height for a triangle get double the area. Drawing the surrounding rectangle shows the triangle fills only half of it.

Counting overlapping areas twice

When splitting an L-shape into two rectangles, some students use overlapping pieces. The pieces must not overlap and must cover the whole shape.

Mixing units

Area is measured in square units. An answer of 24 cm instead of 24 cm² suggests the student is thinking about length.

Worked example: a garden plot

A garden is shaped like a trapezoid with parallel sides 10 m and 6 m, and a height of 4 m. Find its area by decomposing it.

  1. Split the trapezoid into a rectangle 6 m by 4 m and two right triangles, whose bases add up to 10 - 6 = 4 m.
  2. Rectangle: 6 × 4 = 24 square meters.
  3. Triangles together: 1/2 × 4 × 4 = 8 square meters.
  4. Total area: 24 + 8 = 32 square meters.

Answer: The garden has an area of 32 square meters.

Teaching 6.G.A.1

Let students cut paper shapes and rearrange them before writing formulas: a parallelogram becomes a rectangle, two identical triangles become a parallelogram, two identical trapezoids form a parallelogram. Formulas then become summaries of something they have seen.

Assessments frequently show a composite figure with labeled lengths and ask for its area, sometimes including extra lengths that are not needed. Practice choosing the right height is essential.

6 practice questions

Original questions written for this standard. Choose an option or type your answer, then press Check. Every question has a worked explanation.

Score: 0 / 6(0 of 6 checked)
  1. 1.

    A triangle has a base of 12 cm and a height of 7 cm. What is its area in square centimeters?

    Answer and explanation

    Answer: 42 (also accepted: 42 cm²)

    A = 1/2 × 12 × 7 = 42 square centimeters.

  2. 2.

    A parallelogram has a base of 9 in, a height of 4 in and slanted sides of 5 in. What is its area?

    Question 2 options
    Answer and explanation

    Answer: C) 36 in²

    Area of a parallelogram = base × height = 9 × 4 = 36 square inches. The slanted side is not the height.

  3. 3.

    A right triangle has legs of 5 ft and 8 ft. What is its area in square feet?

    Answer and explanation

    Answer: 20

    The legs are perpendicular, so they serve as base and height: 1/2 × 5 × 8 = 20 square feet.

  4. 4.

    An L-shaped room is made of a 10 m by 4 m rectangle and a 3 m by 5 m rectangle that do not overlap. What is the total floor area?

    Question 4 options
    Answer and explanation

    Answer: A) 55 m²

    Add the two rectangles: 10 × 4 = 40 and 3 × 5 = 15, so 40 + 15 = 55 square meters.

  5. 5.

    A trapezoid has parallel sides of 7 cm and 11 cm and a height of 6 cm. What is its area in square centimeters?

    Answer and explanation

    Answer: 54

    Two copies make a parallelogram with base 7 + 11 = 18 and height 6, area 108. Half of that is 54 square centimeters.

  6. 6.

    Why is the area of a triangle half of base times height?

    Question 6 options
    Answer and explanation

    Answer: C) Because two identical triangles fit together to make a parallelogram with that base and height

    Two copies of any triangle form a parallelogram with area b × h, so one triangle has half that area.

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FAQ

Which shapes does 6.G.A.1 include?

Right triangles, other triangles, special quadrilaterals such as parallelograms, trapezoids and rhombuses, and polygons that can be split into these shapes.

Do students have to memorize the trapezoid formula?

The standard emphasizes composing and decomposing shapes. Many students learn the formula, but they should be able to find the area by splitting the shape even without it.

More grade 6 Geometry standards

6.G.A.2: Volume with fractional edge lengths6.G.A.3: Polygons on the coordinate plane6.G.A.4: Nets and surface area
All Grade 6 math standards →Standards home →